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6x^2+3x-360=0
a = 6; b = 3; c = -360;
Δ = b2-4ac
Δ = 32-4·6·(-360)
Δ = 8649
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{8649}=93$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-93}{2*6}=\frac{-96}{12} =-8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+93}{2*6}=\frac{90}{12} =7+1/2 $
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